Question:
The n, l values possible for a sublevel with seven degenerate orbitals are respectively
The n, l values possible for a sublevel with seven degenerate orbitals are respectively
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s(0): 1 orbital, p(1): 3, d(2): 5, f(3): 7. If orbitals = 7, then l must be 3.
Updated On: Jul 4, 2026
- 4, 3
- 3, 4
- 5, 1
- 6, 2
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The Correct Option is A
Solution and Explanation
Step 1: Concept
The number of orbitals in a sublevel is given by the formula $(2l + 1)$.
Step 2: Meaning
Degenerate orbitals are orbitals within the same subshell that have the same energy.
Step 3: Analysis
Setting $2l + 1 = 7$ gives $2l = 6$, so $l = 3$. This corresponds to an 'f' subshell.
Step 4: Conclusion
For $l=3$ to exist, the principal quantum number $n$ must be at least $l+1 = 4$. Thus, the values are $n=4, l=3$. Final Answer: (A)
The number of orbitals in a sublevel is given by the formula $(2l + 1)$.
Step 2: Meaning
Degenerate orbitals are orbitals within the same subshell that have the same energy.
Step 3: Analysis
Setting $2l + 1 = 7$ gives $2l = 6$, so $l = 3$. This corresponds to an 'f' subshell.
Step 4: Conclusion
For $l=3$ to exist, the principal quantum number $n$ must be at least $l+1 = 4$. Thus, the values are $n=4, l=3$. Final Answer: (A)
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