The most suitable reagent for the given conversion is :
Show Hint
- \(\mathrm{LiAlH_4}\)
- \(\mathrm{B_2H_6}\)
- \(\mathrm{NaBH_4}\)
- \(\mathrm{H_2/Pd}\)
The Correct Option is B
Solution and Explanation
LiAlH4 reduces all these groups (ketone to alcohol, amide and nitrile to amines); NaBH4 does not reduce -COOH (it would reduce the ketone); H2/Pd reduces -CN and the ketone but not -COOH.
B2H6 (diborane) reduces carboxylic acids faster than other groups and leaves amide, nitrile and ketone (under controlled conditions) intact - the chemoselective reagent for acid to primary alcohol.
Answer: (2) B2H6
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