The product A formed in the following reaction is:
The Correct Option is C
Approach Solution - 1
To solve this question, we need to identify the product "A" formed in the reaction shown in the image. The reaction involves the conversion of an aromatic amine into its corresponding diazonium salt, followed by a Sandmeyer reaction.
- The starting compound is aniline, \(\text{C}_6\text{H}_5\text{NH}_2\).
- The reaction with \(\text{NaNO}_2\) and \(\text{HCl}\) at \(0^\circ\text{C}\) converts aniline into a diazonium salt, \(\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^−\).
- The resulting diazonium salt then reacts with \(\text{Cu}_2\text{Cl}_2\), a step in the Sandmeyer reaction, replacing the diazonium group with a chlorine atom.
By the completion of these reactions, the diazonium group is replaced by chlorine, resulting in chlorobenzene, \(\text{C}_6\text{H}_5\text{Cl}\).
This yields chlorobenzene as the product "A". The correct option that represents chlorobenzene is shown below:
Conclusion: The product "A" formed in the reaction is chlorobenzene, represented by the correct option above.
Approach Solution -2
In this reaction, aniline (\( C_6H_5NH_2 \)) undergoes diazotization with sodium nitrite (\( \text{NaNO}_2 \)) and hydrochloric acid at \( 0^\circ \text{C} \). The resulting diazonium salt reacts with copper chloride (\( \text{CuCl}_2 \)) to form chlorobenzene (\( C_6H_5Cl \)).
Thus, the product \( A \) is chlorobenzene, \( C_6H_5Cl \).
The Correct Answer is: \( C_6H_5Cl \)
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