Question:

The modulo \(2^N\) counter consist of the following number of states and flip-flops respectively

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Number of states generated by a binary counter: \[ M=2^N \] where \(N\) is the number of flip-flops.
Updated On: Jun 25, 2026
  • \(2N-1\) and \(N-1\)
  • \(2^{2N}\) and \(N-1\)
  • \(2^{N-1}\) and \(N-1\)
  • \(2^N\) and \(N\)
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The Correct Option is D

Solution and Explanation

Concept: An \(N\)-flip-flop binary counter can generate \[ 2^N \] distinct states.

Step 1:
Determine states.
For \(N\) flip-flops, \[ \text{States}=2^N. \]

Step 2:
Determine flip-flops required.
A modulo-\(2^N\) counter requires exactly \[ N \] flip-flops.

Step 3:
Final answer.
\[ \boxed{2^N\text{ states and }N\text{ flip-flops}} \]
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