Question:
The minimum value of \(Z=7x+8y\) subject to \(3x+4y\le24,\ x\ge0,\ y\ge0\) is
The minimum value of \(Z=7x+8y\) subject to \(3x+4y\le24,\ x\ge0,\ y\ge0\) is
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For "$\le$" constraints with $x,y\ge0$, the origin is feasible; check it first for minimization.
Updated On: Oct 17, 2025
- \(56\)
- \(48\)
- \(0\)
- \(-12\)
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The Correct Option is C
Solution and Explanation
All coefficients in \(Z\) are positive and the origin \((0,0)\) is feasible (\(0\le24\)).
Therefore the smallest value occurs at \((0,0)\): \(Z=0\).
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