Question:
The median of Y in the following data is .............
\[ \begin{array}{|c|c|c|c|c|c|c|} \hline \text{Serial number} & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline Y & 22 & 12 & 10 & 14 & 16 & 20 \\ \hline \end{array} \]
The median of Y in the following data is .............
\[ \begin{array}{|c|c|c|c|c|c|c|} \hline \text{Serial number} & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline Y & 22 & 12 & 10 & 14 & 16 & 20 \\ \hline \end{array} \]
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To find the median, arrange the data in ascending order and choose the middle value. If there is an even number of values, take the average of the two middle values.
Updated On: Dec 4, 2025
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Correct Answer: 15
Solution and Explanation
| Serial number | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|
| Y | 22 | 12 | 10 | 14 | 16 | 20 |
To find the median of the values of Y, we first need to arrange the data in ascending order. The given values are 22, 12, 10, 14, 16, and 20.
Sorting these yields: 10, 12, 14, 16, 20, and 22.
The median is the middle value of a data set. Since there are 6 numbers, the median will be the average of the 3rd and 4th values.
Here, the 3rd and 4th values are 14 and 16. The median is calculated as:
\(\text{Median} = \frac{14 + 16}{2} = \frac{30}{2} = 15\)
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