Question:
The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as :
The mean free path for a gas, with molecular diameter $d$ and number density $n$ can be expressed as :
Updated On: May 7, 2026
- $\frac {1}{\sqrt{2} n \pi d}$
- $\frac {1}{\sqrt{2} n \pi d^2}$
- $\frac {1}{\sqrt{2} n^2 \pi d^2}$
- $\frac {1}{\sqrt{2} n^2 \pi^2 d^2}$
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The Correct Option is B
Solution and Explanation
Mean free path for a gas sample $\lambda_{m}=\frac{1}{\sqrt{2}\pi d^{2} n}$
where d is diameter of a gas molecule and n is molecular density
where d is diameter of a gas molecule and n is molecular density
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