Step 1: Determine number of heterozygous gene pairs.
Genotype = Aa Bb Cc Dd → 4 heterozygous loci.
Step 2: Formula for gamete types.
Each heterozygous gene pair produces two possible alleles (A or a, B or b, etc.).
Thus, the total possible gametes = $2^n$, where $n$ = number of heterozygous pairs.
Step 3: Apply formula.
\[
2^4 = 16
\]
Step 4: Conclusion.
Hence, the maximum number of genotypes possible in gametes = 16.