The orbital speed of a satellite depends only on the mass of the central body (in this case, Earth) and the orbital radius. The mass of the satellite itself is irrele vant. Use the formula for orbital speed to find the ratio of speeds
The velocity of a satellite in orbit is given by:
\( v = \sqrt{\frac{GM}{r}} \)
Rearranging the formula, we see that velocity is inversely proportional to the square root of the radius:
\( v \propto \frac{1}{\sqrt{r}} \)
For two different radii, \( r_1 \) and \( r_2 \):
\( \frac{v_1}{v_2} = \sqrt{\frac{r_2}{r_1}} \)
If \( r_2 = 3r_1 \):
\( \frac{v_1}{v_2} = \sqrt{\frac{r_2}{r_1}} = \sqrt{3} \)
The velocity at the smaller radius (\( v_1 \)) is \( \sqrt{3} \) times the velocity at the larger radius (\( v_2 \)).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)