




The major product P formed in the following sequence of reactions is: (i) SOCl2 (ii) R-NH2 (iii) LiAlH4 (iv) H3O+ (1) [Structure with OH and NHR] (2) [Structure with Cl and OH] (3) [Structure with CONHR] (4) [Structure with CH2NHR]
Explanation: 1. SOCl2: Converts the carboxylic acid (-COOH) to an acyl chloride (-COCl). 2. R-NH2: Reacts with the acyl chloride to form an amide (-CONHR). 3. LiAlH4: Reduces the amide to an amine (-CH2NHR). 4. H3O+: Acidic workup to protonate any intermediates. Therefore, the correct answer is (3).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)