The major product of the reaction is
The Correct Option is D
Solution and Explanation
To determine the major product of the given reaction, let's analyze the provided structure and reaction conditions.
The starting material is a bicyclic compound with a double bond and axial hydrogens. The reaction is carried out at 150°C, indicating a possibility of a thermal rearrangement, particularly a Cope rearrangement or something similar due to the high temperature.
The compound is likely undergoing a conformational change leading to a more stable arrangement. The most feasible pathway is an internal rearrangement that relieves strain, possibly involving a ring expansion or contraction that forms a stable product.
In this scenario, the major product would involve the elimination of strain through a rearrangement to give a more favorable, stable product. This involves the migration of the double bond and hydrogens to achieve conjugation or relief of angle strain.
Conclusion: Based on the available options, the image above represents the correct major product of the reaction. This product is the result of the necessary rearrangement to achieve a lower energy state.
Top Questions on Reaction Mechanisms & Synthesis
- The reaction represented by \( A \rightarrow B \) follows first-order kinetics. At a given temperature, 20% of the reaction is completed in 223 s. The time taken to complete 50% of the reaction at the same temperature is _________ s (rounded off to the nearest integer).
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- Consider the following reactions and their standard Gibbs free energies (in J): \[ {Fe(s)} + \frac{1}{2} {O}_2(g) \rightleftharpoons {FeO(s)} \quad \Delta G^\circ = -264900 + 65T \] \[ 2 {H}_2(g) + {O}_2(g) \rightleftharpoons 2 {H}_2{O(g)} \quad \Delta G^\circ = -492900 + 109T \] Assuming Fe and FeO to be pure and no solubility of gases in the solids, the value of \( \frac{p_{H_2O}}{p_{H_2}} \) required to reduce solid FeO to solid Fe at 1000 K is _________ (rounded off to two decimal places). Given: Ideal gas constant \( R = 8.314 \, {J mol}^{-1} {K}^{-1} \).
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- Molten steel at 1900 K having dissolved hydrogen needs to be vacuum degassed. The equilibrium partial pressure of hydrogen to be maintained to achieve 1 ppm (mass basis) of dissolved hydrogen is ......... Torr (rounded off to two decimal places). Given: For the hydrogen dissolution reaction in molten steel \( \left( \frac{1}{2} {H}_2(g) = [{H}] \right) \), the equilibrium constant (expressed in terms of ppm of dissolved H) is: \[ \log_{10} K_{eq} = \frac{1900}{T} + 2.4 \] 1 atm = 760 Torr.
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- Consider the gas phase reaction: \[ CO + \frac{1}{2} O_2 \rightleftharpoons CO_2 \] At equilibrium for a particular temperature, the partial pressures of \( CO \), \( O_2 \), and \( CO_2 \) are found to be \( 10^{-6} \, {atm} \), \( 10^{-6} \, {atm} \), and \( 16 \, {atm} \), respectively. The equilibrium constant for the reaction is ......... \( \times 10^{10} \) (rounded off to one decimal place).
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- In the Claisen-Schmidt reaction to prepare dibenzalacetone from 5.3 g benzaldehyde, a total of 3.51 g of product was obtained. The percentage yield in this reaction was _____.
- JEE Main - 2025
- Chemistry
- Reaction Mechanisms & Synthesis
Questions Asked in IIT JAM CY exam
- Which of the following has tetrahedral coordination?
- IIT JAM CY - 2026
- Coordination chemistry
- Given $C_p = a + bT$
$a = 19.5$, $b = 0.042$, $n = 1$ mole
Temperature changes from $27^\circ C$ to $327^\circ C$.
Find $\Delta H$.
- IIT JAM CY - 2026
- Thermodynamics
- T-shape geometry is shown by
- IIT JAM CY - 2026
- VSEPR theory and shape of molecules
- Compare the M–C bond length in the following complexes:
$Na_2[Mn(CO)_4]$, $Na[Mn(CO)_5]$, $Na[Mn(CO)_6]$.
- IIT JAM CY - 2026
- Organometallic Compounds
- For the reaction: \[ N_2O_3(g) \rightarrow NO(g) + NO_2(g) \] If the degree of dissociation is $\alpha = 0.2$, find $\Delta n_g$ and total number of moles at equilibrium (starting with 1 mole).
- IIT JAM CY - 2026
- Law Of Chemical Equilibrium And Equilibrium Constant