Question:
The major product in the following reaction is
The major product in the following reaction is
Updated On: Nov 17, 2025
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
The given reaction involves the conversion of a ketone into an alkane using sodium hydride (NaH) and Raney nickel (Raney-Ni) with hydrogen gas (H2). Let's break it down step-by-step:
- The initial compound is a cyclic ketone with a dimethylsulfide (SMe2) group. This group serves as a protective group for the ketone.
- Upon treatment with NaH, the deprotonation of the compound occurs. NaH acts as a strong base and is involved in the preliminary preparation step for the reduction.
- Raney-Ni and H2 are then used for the desulfurization process. Raney-Ni is a nickel-aluminium alloy catalyst commonly utilized for hydrogenation reactions.
- The reaction using Raney-Ni and H2 reduces both the SMe2 group and the ketone, ultimately producing an alkane by removing the sulfur and reducing the carbonyl group.
The major product here will be the alkane derivative of the original ketone, where the ketone and the thioether group are reduced completely.
From the given options, the correct product of this reaction sequence is the complete reduction of the ketone into an alkane structure:
This option shows the correct reduction of the ketone into an alkane, accurately reflecting the process using NaH and Raney-Ni/H2.
Was this answer helpful?
0
0
Top Questions on Reaction Mechanisms & Synthesis
- The reaction represented by \( A \rightarrow B \) follows first-order kinetics. At a given temperature, 20% of the reaction is completed in 223 s. The time taken to complete 50% of the reaction at the same temperature is _________ s (rounded off to the nearest integer).
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- Consider the following reactions and their standard Gibbs free energies (in J): \[ {Fe(s)} + \frac{1}{2} {O}_2(g) \rightleftharpoons {FeO(s)} \quad \Delta G^\circ = -264900 + 65T \] \[ 2 {H}_2(g) + {O}_2(g) \rightleftharpoons 2 {H}_2{O(g)} \quad \Delta G^\circ = -492900 + 109T \] Assuming Fe and FeO to be pure and no solubility of gases in the solids, the value of \( \frac{p_{H_2O}}{p_{H_2}} \) required to reduce solid FeO to solid Fe at 1000 K is _________ (rounded off to two decimal places). Given: Ideal gas constant \( R = 8.314 \, {J mol}^{-1} {K}^{-1} \).
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- Molten steel at 1900 K having dissolved hydrogen needs to be vacuum degassed. The equilibrium partial pressure of hydrogen to be maintained to achieve 1 ppm (mass basis) of dissolved hydrogen is ......... Torr (rounded off to two decimal places). Given: For the hydrogen dissolution reaction in molten steel \( \left( \frac{1}{2} {H}_2(g) = [{H}] \right) \), the equilibrium constant (expressed in terms of ppm of dissolved H) is: \[ \log_{10} K_{eq} = \frac{1900}{T} + 2.4 \] 1 atm = 760 Torr.
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- Consider the gas phase reaction: \[ CO + \frac{1}{2} O_2 \rightleftharpoons CO_2 \] At equilibrium for a particular temperature, the partial pressures of \( CO \), \( O_2 \), and \( CO_2 \) are found to be \( 10^{-6} \, {atm} \), \( 10^{-6} \, {atm} \), and \( 16 \, {atm} \), respectively. The equilibrium constant for the reaction is ......... \( \times 10^{10} \) (rounded off to one decimal place).
- GATE MT - 2025
- Mineral Processing and Extractive Metallurgy
- Reaction Mechanisms & Synthesis
- In the Claisen-Schmidt reaction to prepare dibenzalacetone from 5.3 g benzaldehyde, a total of 3.51 g of product was obtained. The percentage yield in this reaction was _____.
- JEE Main - 2025
- Chemistry
- Reaction Mechanisms & Synthesis
View More Questions
Questions Asked in IIT JAM CY exam
- Which of the following has tetrahedral coordination?
- IIT JAM CY - 2026
- Coordination chemistry
- Given $C_p = a + bT$
$a = 19.5$, $b = 0.042$, $n = 1$ mole
Temperature changes from $27^\circ C$ to $327^\circ C$.
Find $\Delta H$.
- IIT JAM CY - 2026
- Thermodynamics
- T-shape geometry is shown by
- IIT JAM CY - 2026
- VSEPR theory and shape of molecules
- Compare the M–C bond length in the following complexes:
$Na_2[Mn(CO)_4]$, $Na[Mn(CO)_5]$, $Na[Mn(CO)_6]$.
- IIT JAM CY - 2026
- Organometallic Compounds
- For the reaction: \[ N_2O_3(g) \rightarrow NO(g) + NO_2(g) \] If the degree of dissociation is $\alpha = 0.2$, find $\Delta n_g$ and total number of moles at equilibrium (starting with 1 mole).
- IIT JAM CY - 2026
- Law Of Chemical Equilibrium And Equilibrium Constant
View More Questions