The major product in Reimer-Tiemann reaction is X. The reactants are Y and Z. X, Y and Z are respectively.
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Reimer-Tiemann with \(\text{CHCl}_3 \rightarrow\) Aldehyde group (-CHO).
Reimer-Tiemann with \(\text{CCl}_4 \rightarrow\) Carboxylic Acid group (-COOH) (Salicylic Acid).
The question asks for the standard Reimer-Tiemann, which usually implies the formylation.
Step 1: Define Reimer-Tiemann Reaction:
This is a standard reaction where Phenol is treated with Chloroform (\(\text{CHCl}_3\)) in the presence of aqueous alkali (NaOH or KOH).
Reaction:
\[ \text{Phenol} + \text{CHCl}_3 + \text{NaOH (aq)} \xrightarrow{340\text{K}} \text{Salicylaldehyde (Major)} + \text{p-Hydroxybenzaldehyde (Minor)} \]
An electrophilic substitution reaction where the electrophile is Dichlorocarbene (\(:\text{CCl}_2\)).
Step 2: Identify X, Y, Z:
- Reactant Y: Phenol.
- Reactant Z: Chloroform (\(\text{CHCl}_3\)) and Alkali.
- Product X: Salicylaldehyde (o-Hydroxybenzaldehyde). The structure has an -OH and a -CHO group at ortho positions on the benzene ring.
Step 3: Match with Options:
Option (C) depicts Salicylaldehyde structure and lists Phenol, \(\text{CHCl}_3\), and Aq. NaOH as components. This is the classic definition.
(Option A seems to be a duplicate or layout variation, but Option C is marked correct in the key).
Final Answer: Option (C).
