




Reaction mechanism: Lithium borohydride (LiBH$_4$) is a selective reducing agent that reduces esters (CO$_2$Et) to alcohols while leaving carboxylic acids (CO$_2$H) unchanged.
Step-by-step process:
Option (A) The ester group (CO$_2$Et) is reduced by LiBH$_4$ in ethanol (EtOH) to form a primary alcohol (-CH$_2$CH$_2$OH).
Option (B) The carboxylic acid group (CO$_2$H) remains unchanged during the reaction.
Option (C) Protonation with H$_3$O$^+$ ensures the stability of the final product.
The final product contains an unchanged carboxylic acid group and a newly formed primary alcohol group, corresponding to option (4).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)