Question

The magnetic intensity at the centre of a long current carrying solenoid is found to be 1.6 x 10³ Am^-1. If the number of turns is 8 per cm, then the current flowing through the solenoid is_____A.

Hint:

Ensure consistent units for turns per meter and current when applying the formula.

Answer 1

Correct Answer: 2

Step 1: Use the formula for magnetic intensity - Magnetic intensity is given by: \[ H = n I, \] where \(n\) is the number of turns per meter and \(I\) is the current. Given: \[ H = 1.6 \times 10^3 \, \text{A/m}, \, n = 8 \, \text{turns/cm} = 800 \, \text{turns/m}. \]

Step 2: Solve for the current - \[ I = \frac{H}{n} = \frac{1.6 \times 10^3}{800}. \] Simplifying: \[ I = 2 \, \text{A}. \]

Final Answer: The current flowing through the solenoid is 2 A.