6 Vm–1 along x-axis
3 Vm–1 along z-axis
6 Vm–1 along z-axis
2 × 10–8 Vm–1 along z-axis
Speed of light,
\(c =\frac wk\)
\(c=\frac {1.5×10^{11}}{0.5×10^3}\)
\(c=3×10^8\ m/sec\)
So, \(E_0=B_0c\)
\(E_0=2×10^{−8}×3×10^8\)
\(E_0=6\ V/m\)
And the direction will be along z-axis.
So, the correct option is (C): 6 Vm–1 along z-axis
Match the LIST-I with LIST-II:
| List-I | List-II | ||
| A. | Radio-wave | I. | is produced by Magnetron valve |
| B. | Micro-wave | II. | due to change in the vibrational modes of atoms |
| C. | Infrared-wave | III. | due to inner shell electrons moving from higher energy level to lower energy level |
| D. | X-ray | IV. | due to rapid acceleration of electrons |
Choose the correct answer from the options given below:
Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}
The waves that are produced when an electric field comes into contact with a magnetic field are known as Electromagnetic Waves or EM waves. The constitution of an oscillating magnetic field and electric fields gives rise to electromagnetic waves.
Electromagnetic waves can be grouped according to the direction of disturbance in them and according to the range of their frequency. Recall that a wave transfers energy from one point to another point in space. That means there are two things going on: the disturbance that defines a wave, and the propagation of wave. In this context the waves are grouped into the following two categories: