Question:

The locus of the extremities of the latus rectum of the family of ellipses \(b^2x^2 + y^2 = a^2b^2\) having a given major axis is

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Endpoints of latus rectum for ellipse: \((\pm a, \frac{b^2}{a})\). Substitute \(b^2\) to get locus.
Updated On: Apr 16, 2026
  • \(x^2 + ay = a^2\)
  • \(y^2 + bx = a^2\)
  • \(x^2 \pm ay = a^2\)
  • None of these
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The Correct Option is A

Solution and Explanation

Concept: Given ellipse: \[ b^2x^2 + y^2 = a^2b^2 \Rightarrow \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \] Major axis is fixed $\Rightarrow$ \(a\) is constant.

Step 1:
Coordinates of latus rectum endpoints.
For ellipse: \[ \text{Endpoints of latus rectum} = (\pm a, \frac{b^2}{a}) \]

Step 2:
Eliminate parameter \(b\).
\[ y = \frac{b^2}{a} \Rightarrow b^2 = ay \]

Step 3:
Substitute into ellipse.
\[ \frac{x^2}{a^2} + \frac{y^2}{ay} = 1 \] \[ \frac{x^2}{a^2} + \frac{y}{a} = 1 \] Multiply by \(a^2\): \[ x^2 + ay = a^2 \] Conclusion: \[ {x^2 + ay = a^2} \]
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