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the locus of the extremities of the latus rectum o
Question:
The locus of the extremities of the latus rectum of the family of ellipses \(b^2x^2 + y^2 = a^2b^2\) having a given major axis is
Show Hint
Endpoints of latus rectum for ellipse: \((\pm a, \frac{b^2}{a})\). Substitute \(b^2\) to get locus.
MET - 2020
MET
Updated On:
Apr 16, 2026
\(x^2 + ay = a^2\)
\(y^2 + bx = a^2\)
\(x^2 \pm ay = a^2\)
None of these
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The Correct Option is
A
Solution and Explanation
Concept:
Given ellipse: \[ b^2x^2 + y^2 = a^2b^2 \Rightarrow \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \] Major axis is fixed $\Rightarrow$ \(a\) is constant.
Step 1:
Coordinates of latus rectum endpoints.
For ellipse: \[ \text{Endpoints of latus rectum} = (\pm a, \frac{b^2}{a}) \]
Step 2:
Eliminate parameter \(b\).
\[ y = \frac{b^2}{a} \Rightarrow b^2 = ay \]
Step 3:
Substitute into ellipse.
\[ \frac{x^2}{a^2} + \frac{y^2}{ay} = 1 \] \[ \frac{x^2}{a^2} + \frac{y}{a} = 1 \] Multiply by \(a^2\): \[ x^2 + ay = a^2 \]
Conclusion:
\[ {x^2 + ay = a^2} \]
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