5
Consider the segment joining the points \( A(1,2) \) and \( B(2,-1) \). The equation of the line that divides this segment in the ratio \( a:b \) is given by: \[ \left( \frac{b}{3a}, -3 \right) \quad \text{and} \quad \left( -3, \frac{-b}{3a} \right). \] Since the line divides the segment in the ratio \( p:q \), this relationship holds.
A random variable X has the following probability distribution
| X= x | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| P(X = x) | 0.15 | 0.23 | k | 0.10 | 0.20 | 0.08 | 0.07 | 0.05 |
For the events E = {x/x is a prime number} and F = {x/x <4} then P(E ∪ F)
5 persons entered a lift cabin in the cellar of a 7-floor building apart from cellar. If each of the independently and with equal probability can leave the cabin at any floor out of the 7 floors beginning with the first, then the probability of all the 5 persons leaving the cabin at different floors is
If a point P moves so that the distance from (0,2) to P is \(\frac{1}{√2 }\) times the distance of P from (-1,0), then the locus of the point P is
Let d be the distance between the parallel lines 3x - 2y + 5 = 0 and 3x - 2y + 5 + 2√13 = 0. Let L1 = 3x - 2y + k1 = 0 (k1 > 0) and L2 = 3x - 2y + k2 = 0 (k2 > 0) be two lines that are at the distance of \(\frac{4d}{√13}\) and \(\frac{3d}{√13}\) from the line 3x - 2y + 5y = 0. Then the combined equation of the lines L1 = 0 and L2 = 0 is:
If (h,k) is the image of the point (3,4) with respect to the line 2x - 3y -5 = 0 and (l,m) is the foot of the perpendicular from (h,k) on the line 3x + 2y + 12 = 0, then lh + mk + 1 = 2x - 3y - 5 = 0.