The limiting molar conductivity of \(AgI\),
\(Λ^0_m(AgI) = Λ^0_m(NaI)+Λ^0_m(AgNO_3)-Λ^0m(NaNO_3)\)
\(Λ^0_m(AgI) = 12.7 + 13.3 – 12.0\)
\(Λ^0_m(AgI) = 26 – 12\)
\(Λ^0_m(AgI) =14\ mS m^2 mol^{–1}\)
So, the answer is \(14\ mS m^2 mol^{–1}\).

In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 