Step 1: Understanding the Concept:
The total area of the floor is equal to the cumulative area of all the carpets required to cover it.
Detailed Explanation:
Let us first find the total area of the floor:
- Area of one carpet = $6\text{ m} \times 4\text{ m} = 24\text{ m}^2$
- Number of carpets required = 34
- Total Area of the hall = $34 \times 24 = 816\text{ m}^2$
Let the breadth of the hall be $b$ meters.
The length of the hall is given as 10 m more than its breadth:
\[ \text{Length } (l) = b + 10 \]
Set up the area equation:
\[ \text{Area} = l \times b \]
\[ 816 = b(b + 10) \]
\[ b^2 + 10b - 816 = 0 \]
Solve the quadratic equation:
\[ b^2 + 34b - 24b - 816 = 0 \]
\[ b(b + 34) - 24(b + 34) = 0 \]
\[ (b + 34)(b - 24) = 0 \]
Since breadth cannot be negative, we have:
\[ b = 24\text{ m} \]
Calculate the length:
\[ l = b + 10 = 24 + 10 = 34\text{ m} \]
Thus, the breadth is 24 m and the length is 34 m.
Step 2: Final Answer:
The dimensions are 24 m and 34 m, matching Option (C).