Question:
The ionic conductance of \( \text{Ba}^{2+} \) and \( \text{Cl}^- \) respectively are 127 and 76 \( \text{S} \, \text{cm}^{-1} \) at infinite dilution. The equivalent conductance of \( \text{BaCl}_2 \) at infinite dilution will be:
The ionic conductance of \( \text{Ba}^{2+} \) and \( \text{Cl}^- \) respectively are 127 and 76 \( \text{S} \, \text{cm}^{-1} \) at infinite dilution. The equivalent conductance of \( \text{BaCl}_2 \) at infinite dilution will be:
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The equivalent conductance at infinite dilution is the sum of the conductances of the ions involved.
Updated On: Mar 25, 2026
- 330 \( \Omega^{-1} \text{cm}^2 \)
- 203 \( \Omega^{-1} \text{cm}^2 \)
- 139 \( \Omega^{-1} \text{cm}^2 \)
- 51 \( \Omega^{-1} \text{cm}^2 \)
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The Correct Option is C
Solution and Explanation
Step 1: Calculate equivalent conductance.
The equivalent conductance of a salt at infinite dilution is the sum of the conductances of its ions: \[ \Lambda = \lambda_{\text{Ba}^{2+}} + \lambda_{\text{Cl}^-} = 127 + 76 = 139 \, \Omega^{-1} \text{cm}^2 \] Thus, the correct answer is (3).
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