Question:
The ion with 4f$^7$ configuration is:
The ion with 4f$^7$ configuration is:
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Subtract the ion charge from atomic number to determine electronic configuration. Eu$^{2+}$ is a half-filled 4f$^7$ stable configuration.
Updated On: Mar 18, 2026
- Pr$^{3+}$
- Lu$^{3+}$
- Eu$^{2+}$
- Ce$^{4+}$
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The Correct Option is C
Solution and Explanation
Europium (Z = 63). Eu$^{2+}$ means 63 – 2 = 61 electrons. Configuration: [Xe] 4f$^7$ — hence correct.
Pr$^{3+}$ → 58 – 3 = 55 → 4f$^2$
Lu$^{3+}$ → 71 – 3 = 68 → 4f$^{14}$
Ce$^{4+}$ → 58 – 4 = 54 → [Xe] → no 4f electrons.
Pr$^{3+}$ → 58 – 3 = 55 → 4f$^2$
Lu$^{3+}$ → 71 – 3 = 68 → 4f$^{14}$
Ce$^{4+}$ → 58 – 4 = 54 → [Xe] → no 4f electrons.
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