The frequency distributions of a trait in two populations, X and Y, are shown in the figure.

Which one of the following statements about the mean and standard deviation (SD) of the two populations is accurate?
Step 1: Analyze the mean.
The mean is determined by the center of the distribution. In the graph, Population X has a sharply peaked distribution, while Population Y has a wider distribution. This suggests that Population Y has a lower peak, indicating that its mean is higher than Population X.
Step 2: Analyze the standard deviation (SD).
The standard deviation measures the spread of the data. A wider distribution indicates a higher SD. Since Population Y has a wider distribution, it also has a higher SD compared to Population X, which has a narrower distribution.
Step 3: Conclusion.
Thus, based on the shape of the frequency distributions, we conclude that Population Y has both a higher mean and a higher SD than Population X.
Final Answer: \boxed{(D)}
Which one of the options can be inferred about the mean, median, and mode for the given probability distribution (i.e. probability mass function), $P(x)$, of a variable $x$?

An ornamental shrub species was brought from Japan in the early 1800s to India, where it was planted frequently in gardens and parks. The species persisted for many decades without spreading, and then began to spread invasively fifty years ago. Which one or more of the following processes could have led to it becoming invasive?
Which one or more of the following is/are greenhouse gas(es)?