Question

What is the approximate percentage of schools, where the enrolment was below 120?

• A. 59.16
• B. 59.27
• C. 60
• D. 61
• A. 56
• B. 56.39
• C. 57
• D. 55
• A. 100-119
• B. 80-99
• C. 60-79
• D. None of these
• A. 8
• B. 9.5
• C. 9
• D. 10
• A. 2550
• B. 2033
• C. 1833
• D. 1316
• A. 107.87
• B. 217.60
• C. 109.5
• D. 129.5

Answer 1

The Correct Option is A

The percentage of schools, where the enrolment was below 120 = \(\frac{\text{Total Schools where the enrolments are not above 120}}{\text{Total number of schools}} \times 100\)

= \(\frac{526+620+674+717+681}{5439} \times 100\)

= \(\frac{3218}{5439} \times 100\)

≈ 59.16%

The correct option is (A): 59.16

Answer 2

The percentage of schools, where the enrolment was above 79 but below 180 = \(\frac{\text{Total Schools where the enrolments are above 79 and below 180}}{\text{Total number of schools}} \times 100\)

= \(\frac{717+681+612+540+517}{5439}\)

= \(\frac{3067}{5439} \times 100\)

≈ 56.39%

The correct option is (B): 56.39

Answer 3

According to the table, enrolments that under the class 80-99 is the maximum with 717 schools

The correct option is (B): 80-99

Answer 4

The class 160-179 has the least number of schools = 517

Formula for % = \(\frac{\text{The least number of schools}}{\text{Total Numbe rof schools}} \times 100\)

= \(\frac{517}{5439} \times 100\)

≈ 9.5%

The correct option is (B): 9.5

Answer 5

No. of schools with enrolment above 99 & below 160 = 681, 612, 540

The number of schools where the enrolment is above 99 but below 1607 = 681 + 612 + 540

= 1833

The correct option is (C): 1833

Answer 6

Average enrolment will be = \(\frac{\text{Mean of every enrolment}}{\text{Total Count of enrolment}}\)

= \(\frac{29.5+ 49.5 + 69.5 + 89.5 + 109.5 + 129.5 + 149.5 + 169.5 + 189.5}{9}\)

= 109.5

The correct option is (C): 109.5