| Age/Gender Groups | TotalPopulation (Million) | In School | Not In School and Working | Not InSchool And not Working | Total ChildPopulation not in School (Millions) |
| Rural males (5-9) | 39.7 | 67.2 | 1.3 | 31.5 | 13.02 |
| Rural females (5-9) | 35.7 | 56.2 | 3 | 40.8 | 15.63 |
| Urban males (5-9) | 11.3 | 84.1 | 0.3 | 15.2 | 1.79 |
| Urban Females (5-9) | 10.2 | 80.1 | 1.3 | 18.6 | 2.02 |
| Rural males (10-14) | 36.1 | 76.6 | 12.8 | 10.6 | 8.44 |
| Rural females (10-14) | 30.3 | 55.7 | 30.3 | 14 | 13.42 |
| Urban males (10-14) | 11.7 | 87.2 | 7 | 5.8 | 1.5 |
| Urban females (10-14) | 10.5 | 81.6 | 13.1 | 5.3 | 1.93 |
| Total | 185.5 | 57.79 |
Population of Rural males (in millions) of age group (5-9) = 39.7
Population of Rural males (in millions) of age group (10-14) = 36.1
The average of Rural Males Population in millions = \(\frac{\text{Total Rural Males}}{2}\)
= \(\frac{36.1 + 39.7}{2}\)
= 37.9
The correct option is (C): 37.9
The Percentage of children in school in category = \(\frac{\text{In school}}{\text{Total Population}} \times 100\)
Urban males (5-9) = \(\frac{84.1}{100} \times 11.3\) = 84.1%
Rural males (5-9) = \(\frac{67.2}{100} \times 69.7\) = 67.2%
Urban females (5-9) = \(\frac{80.1}{100} \times 10.2\) = 80.1%
Rural females (10-14) = \(\frac{55.7}{100} \times 30.3\) = 55.7%
The minimum is Rural females of age group (10-14)
The correct option is (D):Rural females 10-14
From the table, Total number of children (in millions) not in school = 57.79
Percentage = \(\frac{\text{Children not in school}}{\text{Total population}} \times 100\)
= \(\frac{57.79}{185.5} \times 100\)
≈ 31.13%
The correct option is (D): 31.13
Total Urban males (in millions) not in school (both age group) = 1.79 + 1.5 = 3.29
Total Rural males (in millions) not in school (both age group) = 13.02 + 8.44 = 21.46
Percentage = \(\frac{\text{Urban Males not in school}}{\text{Rual males not in school}} \times 100\)
= \(\frac{3.29}{21.46} \times 100\)
≈ 15.33
The correct option is (C): 15.33
In the forth column of the table The number of children who are working is given,
Rural males of age group (5-9) working (in millions) = \(\frac{1.3}{100} \times 39.7 = 0.5161 million\)
Rural females of age group (5-9) working (in millions) = \(\frac{3}{100} \times 100 = 1.071 million\)
Adding both the number the approx. will be 18
The correct option is (B): 18
Number of children not in school and not working in all categories (in millions)
= \( (\frac{31.5}{100} \times 13.02) + (\frac{40.8}{100} \times 15.63) + (\frac{15.2}{100} \times 1.79) + (\frac{18.6}{100} \times 2.02) + (\frac{10.6}{100} \times 8.44) + (\frac{14}{100} \times 13.32) + (\frac{5.8}{100} \times 1.5) + (\frac{5.3}{100} \times 1.93)\)
= 14.08
So, the requires Percentage will be = \(\frac{14.08}{57.79} \times 100\)
≈ 24.36%
The correct option is (D): None of these
To find out The Number of children (in millions) not in school and not working in the category
we have to,
Rural females of group (10-14) = \(\frac{14}{100} \times 13.42\) = 1.88
Rural males of group (5-9) = \(\frac{31.5}{100} \times 13.02\) = 4.10
Rural females of group (5-9) = \(\frac{40.8}{100} \times 15.63\) = 6.37
Urban males of group (10-14) = \(\frac{5.8}{100} \times 1.5\)
The highest is Rural females of group (5-9)
The correct option is (C): Rural females 5-9
Number of children (in millions) not in school but working in the category
We have to,
Rural males of age group (10-14) = \(\frac{12.8}{100} \times 8.44\) = 1.08
Rural females of age group (10-14) = \(\frac{30.3}{100} \times 13.42\) = 4.06
Urban females of age group (10-14) = \(\frac{13.1}{100} \times 1.93\) = 0.25
Urban males of age group (10-14) = \(\frac{7}{100} \times 1.5\) = 0.10
The highest is Rural females of age group (10-14)
The correct option is (B): Rural females 10-14
From the table we know that,
Total child population not in school (in millions) = 57.79
Total child population in school (in millions) = 185.5 − 57.79 = 127.71
The Percentage of the total population of the children of all categories is in the school = \(\frac{127.71}{185.5} \times 100\)
= 68.87%
The correct option is (A): 68.87
From the table we know that,
Total child population not in school (in millions) = 57.79
Total child population in school (in millions) = 185.5 − 57.79 = 127.71
The percentage ratio between the total number of children not in school and in school = \(\frac{57.79}{127.71} \times 100\)
= 45.20%
The correct option is (C): 45.20
The table provided displays the estimated cost (in lakh) for the construction of a canal between two points. Based on the information in the table, answer the questions that follow.
The following table gives the marks obtained by six students in six different subjects in an examination. The maximum marks for each subject are given in the brackets. Answer the questions that follow.
Consider the provided scenario and answer the following questions based on the given information.

