Question:

The following table gives data collected for an online job portal, InfiniteJobs.com. For each question in this set, there are two statements, X and Y, each of which could be True or False. Choose the option that correctly describes both statements.

YearCategoryNumber of RegistrationsNumber of Candidates who posted their CVsNumber of Candidates short-listed by EmployersNumber of offered jobs
2004Technical61,20559,981684181
2004Managerial19,23615,38913848
2005Technical63,29860,133637115
2005Managerial45,29240,76339984

Statement X: The percentage increase in the number of Registrations from 2004 to 2005 is higher for Managerial candidates than for Technical candidates.
Statement Y: The overall Registrations have grown by more than 25%.

Show Hint

Work out percentage change separately for Managerial and Technical registrations, then compare the combined 2004 and 2005 totals against a 25% benchmark.
Updated On: Jul 14, 2026
  • Only [X] is True
  • Only [Y] is True
  • Both [X] and [Y] are True
  • Neither [X] nor [Y] is True
Show Solution
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept.
We need to check two separate claims using the percentage change formula, \(\%\text{ change} = \frac{\text{new}-\text{old}}{\text{old}}\times 100\).

Step 2: Test Statement X, Managerial registrations.
Managerial registrations went from 19,236 in 2004 to 45,292 in 2005.
\[ \%\text{ increase} = \frac{45{,}292-19{,}236}{19{,}236}\times 100 = \frac{26{,}056}{19{,}236}\times 100 \approx 135.45\% \]

Step 3: Test Statement X, Technical registrations.
Technical registrations went from 61,205 in 2004 to 63,298 in 2005.
\[ \%\text{ increase} = \frac{63{,}298-61{,}205}{61{,}205}\times 100 = \frac{2{,}093}{61{,}205}\times 100 \approx 3.42\% \]
Since \(135.45\%\) is far bigger than \(3.42\%\), Managerial's percentage increase is indeed higher, so Statement X is True.

Step 4: Test Statement Y, overall registrations.
Total registrations in 2004: \(61{,}205+19{,}236=80{,}441\). Total registrations in 2005: \(63{,}298+45{,}292=108{,}590\).
\[ \%\text{ increase} = \frac{108{,}590-80{,}441}{80{,}441}\times 100 = \frac{28{,}149}{80{,}441}\times 100 \approx 35.0\% \]
Since \(35\%\) is greater than \(25\%\), Statement Y is True as well.

Step 5: Final Answer.
Both X and Y check out as true statements, so both together are correct. \[ \boxed{\text{Both [X] and [Y] are True}} \]
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