Question:
The following reaction is an example of ... reaction.
\(\mathrm{C_2H_4Br_2 \xrightarrow{Alc.\ KOH} C_2H_2}\)
The following reaction is an example of ... reaction.
\(\mathrm{C_2H_4Br_2 \xrightarrow{Alc.\ KOH} C_2H_2}\)
\(\mathrm{C_2H_4Br_2 \xrightarrow{Alc.\ KOH} C_2H_2}\)
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Alcoholic KOH is used for elimination reactions (dehydrohalogenation).
Updated On: Apr 20, 2026
- addition
- dehydrobromination
- substitution
- bromination
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
Removal of HBr from a vicinal dibromide gives an alkyne.
Step 2: Detailed Explanation:
C\(_2\)H\(_4\)Br\(_2\) (1,2-dibromoethane) with alcoholic KOH undergoes two successive dehydrohalogenations to form ethyne (C\(_2\)H\(_2\)).
BrCH\(_2\)CH\(_2\)Br \(\xrightarrow{Alc.\ KOH}\) CH\(_2\)=CHBr \(\xrightarrow{Alc.\ KOH}\) HC≡CH. This is dehydrobromination.
Step 3: Final Answer:
Dehydrobromination
Removal of HBr from a vicinal dibromide gives an alkyne.
Step 2: Detailed Explanation:
C\(_2\)H\(_4\)Br\(_2\) (1,2-dibromoethane) with alcoholic KOH undergoes two successive dehydrohalogenations to form ethyne (C\(_2\)H\(_2\)).
BrCH\(_2\)CH\(_2\)Br \(\xrightarrow{Alc.\ KOH}\) CH\(_2\)=CHBr \(\xrightarrow{Alc.\ KOH}\) HC≡CH. This is dehydrobromination.
Step 3: Final Answer:
Dehydrobromination
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