Question:

The first and second ionisation enthalpies of a metal are 496 and 4560 kJ mol\(^{-1}\), respectively. How many moles of HCl and \(\mathrm{H_2SO_4}\), respectively, will be needed to react completely with 1 mole of the metal hydroxide ?

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IE\(_2\) is about 9 times IE\(_1\), so the metal forms a +1 ion (group 1) and its hydroxide is MOH.
Updated On: Nov 5, 2026
  • 1 and 2
  • 1 and 0.5
  • 1 and 1
  • 2 and 0.5
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The Correct Option is B

Solution and Explanation

IE\(_1\) = 496 kJ/mol (low) and IE\(_2\) = 4560 kJ/mol (a huge jump, about 9 times). The large jump means the second electron comes from a stable noble-gas core, so the metal has one valence electron: an alkali metal (Na, IE\(_1\) = 496).
Its hydroxide is MOH.
MOH + HCl \(\rightarrow\) MCl + \(\mathrm{H_2O}\): 1 mol MOH needs 1 mol HCl.
2MOH + \(\mathrm{H_2SO_4}\) \(\rightarrow\) \(\mathrm{M_2SO_4}\) + 2\(\mathrm{H_2O}\): 1 mol MOH needs 0.5 mol \(\mathrm{H_2SO_4}\).
Answer: (2) 1 and 0.5
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