The question is about finding the element with the highest first ionization enthalpy among the given options. Ionization enthalpy is the energy required to remove an electron from a gaseous atom or ion.
Explanation:
Let's analyze each element:
From the above analysis, Nitrogen (N) has the highest first ionization enthalpy among the given elements due to its position in the periodic table, small atomic size, and stable half-filled configuration.
Conclusion: The correct answer is \(N\).
The order of first ionization enthalpy (\( I_{E_1} \)) for these elements is:
\(\text{Al} < \text{Si} < \text{C} < \text{N}\)
Thus, nitrogen (\( \text{N} \)) has the highest first ionization enthalpy among the given options.
The Correct Answer is: N
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| List-I | List-II |
|---|---|
| A. Melting point [K] | I. Tl > In > Ga > Al > B |
| B. Ionic Radius [M3/pm] | II. B > Tl > Al ≈ Ga ≈ In |
| C. ΔiH1 [kJ mol-1] | III. Tl > In > Al > Ga > B |
| D. Atomic Radius [pm] | IV. B > Al > Tl > In > Ga |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)