Question

The equation of an alternating current is \(14\sin(1256t)\), determine the frequency.

• A. 100 Hz
• B. 50 Hz
• C. 150 Hz
• D. 200 Hz

Hint:

To find the frequency from the angular frequency, use the formula \( f = \frac{\omega}{2\pi} \).

Answer 1

The Correct Option is D

The equation of the alternating current is in the form \( A\sin(\omega t) \), where \( \omega = 2\pi f \) is the angular frequency. Given \( \omega = 1256 \), we can calculate the frequency \( f \) as: \[ f = \frac{\omega}{2\pi} = \frac{1256}{2\pi} \approx 200 \, \text{Hz} \]