Question:

The equation of a straight line whose slope is \(\frac13\) and which divides the line joining the points \(A(0,2)\) and \(B(5,-3)\) in the ratio \(4:7\) is

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First find the dividing point using section formula, then apply point-slope form.
Updated On: Jul 15, 2026
  • \(9x-14y+3=0\)
  • \(11x+33y-16=0\)
  • \(11x-33y-14=0\)
  • \(x-3y-2=0\)
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The Correct Option is C

Solution and Explanation

Let point \(P\) divide \(AB\) in ratio \(4:7\). Using section formula: \[ P=\left(\frac{4(5)+7(0)}{11},\frac{4(-3)+7(2)}{11}\right) \] \[ P=\left(\frac{20}{11},\frac{2}{11}\right) \] Slope given: \[ m=\frac13 \] Use point-slope form: \[ y-\frac{2}{11}=\frac13\left(x-\frac{20}{11}\right) \] Multiply by \(33\): \[ 33y-6=11x-20 \] Rearrange: \[ 11x-33y-14=0 \] Thus, \[ \boxed{11x-33y-14=0} \]
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