The question asks to identify the element that does not belong to the same period as the others in the modern periodic table. Let's analyze the given elements one by one:
From this analysis, we observe:
Therefore, the element only belonging to the 5th period and differing from the rest is Palladium (Pd).
Conclusion: The element that does not belong to the same period as the remaining elements is Palladium, which is the correct answer.
In the modern periodic table, elements are arranged in periods (rows) based on their atomic numbers. To determine which element does not belong to the same period as the others, we need to identify the periods of the given elements:
The elements Iridium, Osmium, and Platinum are all in period 6. Palladium, however, is in period 5, making it the element that does not belong to the same period as the others. Therefore, Palladium is the correct answer.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
Which of the following Statements are NOT true about the periodic table?
A. The properties of elements are a function of atomic weights.
B. The properties of elements are a function of atomic numbers.
C. Elements having similar outer electronic configuration are arranged in the same period.
D. An element's location reflects the quantum numbers of the last filled orbital.
E. The number of elements in a period is the same as the number of atomic orbitals available in the energy level that is being filled.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)