| List-I | List-II |
|---|---|
| A. Melting point [K] | I. Tl > In > Ga > Al > B |
| B. Ionic Radius [M3/pm] | II. B > Tl > Al ≈ Ga ≈ In |
| C. ΔiH1 [kJ mol-1] | III. Tl > In > Al > Ga > B |
| D. Atomic Radius [pm] | IV. B > Al > Tl > In > Ga |
To match the items from List I with List II:
A. Melting point [K]: Based on the trend, Tl > In > Ga > Al > B. (Matches I).
B. Ionic Radius [M$^{+3}$/pm]: Boron has the smallest ionic size, followed by Tl > Al $\approx$ Ga > In (Matches II).
C. $\Delta_i H_1$ [kJ mol$^{-1}$]: Ionization enthalpy follows the trend Tl > In > Al > Ga > B.(Matches III).
D. Atomic Radius [pm]: Atomic radius increases as B > Al > Tl > In > Ga.(Matches IV).
Correct Answer: (3)
The given circuit works as: 
Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}