To determine the electronic configuration of Einsteinium (Es), we need to follow the order of filling electrons into atomic orbitals according to the Aufbau principle, Hund's rule, and the Pauli exclusion principle.
The atomic number of Einsteinium is 99, indicating that it has 99 electrons.
General electronic configuration order is: \(1s \to 2s \to 2p \to 3s \to 3p \to 4s \to 3d \to 4p \to 5s \to 4d \to 5p \to 6s \to 4f \to 5d \to 6p \to 7s \to 5f \to 6d \to 7p\)
Let's break it down step by step for Einsteinium:
Therefore, the full electron configuration of Einsteinium is written as \([Rn] \ 5f^{11} \ 6d^0 \ 7s^2\).
The correct option is:
[Rn] \( 5f^{11} 6d^0 7s^2 \)
The question asks for the electronic configuration of the element Einsteinium, which has an atomic number of 99. In order to determine the correct electronic configuration, we need to understand how electrons fill the atomic orbitals based on their energy levels, following the Aufbau principle.
This configuration respects the electron filling order and Pauli's exclusion principle. Thus, option (2) is the correct electronic configuration of Einsteinium.
The figures below show:
Which of the following points in Figure 2 most accurately represents the nodal surface shown in Figure 1?
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The given circuit works as: 
Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}