Question:
The electric field strength at a point in an electric field is $30\,N/C$. Find the force experienced by a charge of $20\,C$ at that point.
The electric field strength at a point in an electric field is $30\,N/C$. Find the force experienced by a charge of $20\,C$ at that point.
Show Hint
Remember the relation:
\[
F=qE
\]
Force is directly proportional to both charge and electric field strength.
Updated On: Jun 5, 2026
- $600\,N$
- $30\,N$
- $20\,N$
- $300\,N$
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The Correct Option is A
Solution and Explanation
Concept:
Electric field intensity is defined as force per unit positive charge.
\[
E=\frac{F}{q}
\]
Therefore,
\[
F=qE
\]
Step 1: Write the given data. \[ E=30\,N/C \] \[ q=20\,C \]
Step 2: Substitute into the formula. \[ F=qE \] \[ F=(20)(30) \] \[ F=600\,N \]
Step 3: State the answer. Hence the force acting on the charge is \[ 600\,N \] center minipage0.35
Force = $600\,N$ minipage center
Step 1: Write the given data. \[ E=30\,N/C \] \[ q=20\,C \]
Step 2: Substitute into the formula. \[ F=qE \] \[ F=(20)(30) \] \[ F=600\,N \]
Step 3: State the answer. Hence the force acting on the charge is \[ 600\,N \] center minipage0.35
Force = $600\,N$ minipage center
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