Step 1: Effect of dielectric on electric field.
A dielectric reduces the effective electric field inside the capacitor:
$E' = \dfrac{E}{\kappa}$, where $\kappa>1$.
Thus, $E'<E$.
Step 2: Effect of dielectric on capacitance.
Capacitance increases by a factor $\kappa$:
$C' = \kappa C$
So $C'>C$.
Step 3: Evaluate options.
Only option (B) correctly states both effects: reduced electric field and increased capacitance.
Step 4: Conclusion.
Thus, $E'<E$ and $C'>C$.