The position of a particle along the y-axis is $y = P t^4 + Q$. For dimensional consistency, the dimension of $P$ in terms of length [L] and time [T] is
Show Hint
Always equate dimensions of every term in an equation; they must match exactly.
Step 1: Apply dimensional analysis.
Given: $y = P t^{4} + Q$.
Since $y$ has dimension [L] and $Q$ is a length constant,
$P t^{4}$ must also have dimension [L]. Step 2: Determine the dimension of $P$.
$[P][T^{4}] = [L]$.
Therefore,
$[P] = \dfrac{[L]}{[T^4]} = L T^{-4}$. Step 3: Conclusion.
Hence, the dimension of $P$ is $L T^{-4}$.