The magnetic field \( B \) is initially given by the equation:
Step 1: \( B = \frac{\mu_0 i}{2R} \times 4 \), which is the original magnetic field expression.
Step 2: For the new radius \( R' = 4R \), the new field \( B' \) is given by:
Step 3: Substitute \( R' \) into the magnetic field formula: \( B' = \frac{\mu_0 i}{2R'} = \frac{\mu_0 i}{8R} \).
Step 4: Now, calculate the ratio \( \frac{B'}{B} = \frac{1}{16} \), indicating that the new magnetic field is \( \frac{1}{16} \) of the original field.
Step 5: With this ratio, we conclude that the new magnetic field \( B' \) is \( 2T \).

A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where