The correct answer is (C) : \(2\sqrt2\)
AB = x – 2y + 1 = 0
AC = 2x – y - 1 = 0
So A(1, 1)

Altitude from B is BH \(= x + 2y – 7 = 0 ⇒ B (3, 2) \)
Altitude from C is CH \(= 2x + y – 7 = 0 ⇒ C (2, 3) \)
Centroid of ΔABC = E(2, 2) OE = \(2\sqrt2\)
In a △ABC, suppose y = x is the equation of the bisector of the angle B and the equation of the side AC is 2x−y = 2. If 2AB = BC and the points A and B are respectively (4, 6) and (α, β), then α + 2β is equal to:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)