Question:

The distance (in meter) for 7 throws of a shotputter are \(14.5,15.2,16.8,17.1,15.9,16.3,14.7\). Calculate sample mean and sample standard deviation.

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For sample standard deviation always divide by \(n-1\), not by \(n\).
Updated On: Jun 11, 2026
  • \(14.79,\;0.88\)
  • \(15.79,\;1.02\)
  • \(14.79,\;1.15\)
  • \(15.79,\;0.96\)
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The Correct Option is D

Solution and Explanation

Step 1: Find the sample mean.
\[ \bar x = \frac{14.5+15.2+16.8+17.1+15.9+16.3+14.7}{7} \] \[ = \frac{110.5}{7} \] \[ = 15.7857 \] \[ \bar x\approx15.79. \]

Step 2: Compute deviations from mean and square them.
After calculation, \[ \sum (x_i-\bar x)^2 \approx5.49. \]

Step 3: Calculate sample standard deviation.
\[ s = \sqrt{\frac{\sum(x_i-\bar x)^2}{n-1}} \] \[ = \sqrt{\frac{5.49}{6}} \] \[ = \sqrt{0.915} \] \[ \approx0.96. \] Therefore, \[ \boxed{(\bar x,s)=(15.79,\;0.96)} \]
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