Question:
The difference of the focal distances of any point on the hyperbola is equal to its
The difference of the focal distances of any point on the hyperbola is equal to its
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For hyperbola, $|PF_1 - PF_2| = 2a$.
Updated On: Apr 8, 2026
- latus rectum
- eccentricity
- length of the transverse axis
- half the length of the transverse axis
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
For hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$, foci are $(\pm ae, 0)$.
Step 2: Detailed Explanation:
For any point $P(x,y)$ on hyperbola, $|PF_1 - PF_2| = 2a$, which is the length of the transverse axis.
Step 3: Final Answer:
The difference of focal distances equals the length of the transverse axis.
For hyperbola $\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$, foci are $(\pm ae, 0)$.
Step 2: Detailed Explanation:
For any point $P(x,y)$ on hyperbola, $|PF_1 - PF_2| = 2a$, which is the length of the transverse axis.
Step 3: Final Answer:
The difference of focal distances equals the length of the transverse axis.
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