Question:
The difference in bond angles between $\text{SO}_2$ and $\text{H}_2\text{O}$ is:
The difference in bond angles between $\text{SO}_2$ and $\text{H}_2\text{O}$ is:
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More lone pairs produce greater repulsion and stronger compression of bond angles. Hence $\text{H}_2\text{O}$ has a much smaller bond angle than $\text{SO}_2$.
Updated On: Jun 15, 2026
- $12.5^\circ$
- $17.5^\circ$
- $15.0^\circ$
- $13.0^\circ$
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The Correct Option is C
Solution and Explanation
Concept:
\[
\text{SO}_2
\]
has $sp^2$ hybridization with one lone pair and a bent geometry.
Its bond angle is approximately
\[
119.5^\circ
\]
Water has $sp^3$ hybridization with two lone pairs and a bent geometry.
Its bond angle is
\[
104.5^\circ
\]
Step 1: Calculate the difference \[ \Delta\theta = 119.5^\circ-104.5^\circ \] \[ \Delta\theta = 15.0^\circ \] Therefore, \[ \boxed{15.0^\circ} \]
Step 1: Calculate the difference \[ \Delta\theta = 119.5^\circ-104.5^\circ \] \[ \Delta\theta = 15.0^\circ \] Therefore, \[ \boxed{15.0^\circ} \]
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