Question:

The shapes of $BrF_{5}$ and $XeF_{4}$, respectively are}

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$AB_{5}L_{1}$ is Square Pyramidal; $AB_{4}L_{2}$ is Square Planar.
Updated On: May 12, 2026
  • square pyramid, square pyramid
  • square planar, square planar
  • square planar, square pyramid
  • square pyramid, square planar
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The Correct Option is D

Solution and Explanation


Step 1: Concept

The shape is determined by VSEPR theory, considering the number of bond pairs and lone pairs on the central atom.

Step 2: Meaning

$BrF_{5}$: Bromine has 7 valence electrons. 5 are used for bonding, leaving 1 lone pair. Steric number $= 5 + 1 = 6$ ($sp^{3}d^{2}$ hybridization). $XeF_{4}$: Xenon has 8 valence electrons. 4 are used for bonding, leaving 2 lone pairs. Steric number $= 4 + 2 = 6$ ($sp^{3}d^{2}$ hybridization).

Step 3: Analysis

For $BrF_{5}$, octahedral geometry with 1 lone pair results in a square pyramidal shape. For $XeF_{4}$, octahedral geometry with 2 lone pairs (placed opposite to each other) results in a square planar shape.

Step 4: Conclusion

The respective shapes are square pyramid and square planar. Final Answer: (D)
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