Concept:
When every element of a matrix is multiplied by a constant \( k \), the determinant of the matrix is multiplied by \( k^n \), where \( n \) is the order (size) of the square matrix.
Given:
The matrix is of order \( 3 \times 3 \), and the original determinant is \( 8 \).
Each element is multiplied by \( -2 \).
Step-by-step Calculation:
Since it's a 3 × 3 matrix, the new determinant becomes:
\[
\text{New Determinant} = (-2)^3 \times 8 = -8 \times 8 = -64
\]
✔️ Final Answer: The determinant of the modified matrix is \( -64 \).