The degree of differential equation
\[
9 \frac{d^2y}{dx^2} = \left\{ 1 + \left( \frac{dy}{dx} \right)^2 \right\}^{\frac{1}{3}} \text{ is}
\]
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To find the degree of a differential equation, first eliminate all radicals and fractions. Then identify the highest order derivative and note its power. That power is the degree.
We need to find the degree of the given differential equation.
Step 1: Recall the definition of degree of a differential equation.
The degree of a differential equation is defined as:
- The power of the highest order derivative
- After the equation has been made free from radicals and fractions
- Provided the equation is a polynomial in all derivatives
Step 2: Write the given equation.
\[
9 \frac{d^2y}{dx^2} = \left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^{\frac{1}{3}}
\]
Step 3: Remove the radical (cube root).
To make the equation free from radicals, we raise both sides to the power 3:
\[
\left[ 9 \frac{d^2y}{dx^2} \right]^3 = 1 + \left( \frac{dy}{dx} \right)^2
\]
Step 4: Simplify the left-hand side.
\[
9^3 \left( \frac{d^2y}{dx^2} \right)^3 = 1 + \left( \frac{dy}{dx} \right)^2
\]
\[
729 \left( \frac{d^2y}{dx^2} \right)^3 = 1 + \left( \frac{dy}{dx} \right)^2
\]
Step 5: Identify the highest order derivative.
The highest order derivative in the equation is \(\frac{d^2y}{dx^2}\) (second order derivative).
In the equation \(729 \left( \frac{d^2y}{dx^2} \right)^3 = 1 + \left( \frac{dy}{dx} \right)^2\), the highest order derivative \(\frac{d^2y}{dx^2}\) appears with power 3.
Step 6: Determine the degree.
The degree is the power of the highest order derivative, which is 3.
Step 7: Conclusion.
The degree of the given differential equation is 3. Final Answer: (C) 3