Question:

The current \(I\) drawn from the \(5\,\text{V}\) source will be: center
center

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For complicated resistor networks, first identify symmetry and balanced bridge conditions to simplify the circuit rapidly.
Updated On: Jun 17, 2026
  • \(0.67\,\text{A}\)
  • \(2\,\text{A}\)
  • \(0.33\,\text{A}\)
  • \(0.5\,\text{A}\)
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The Correct Option is D

Solution and Explanation

By symmetry and proper reduction of bridge network, equivalent resistance becomes: \[ R_{eq}=10\Omega \] Using Ohm’s law: \[ I=\frac{V}{R} \] \[ I=\frac{5}{10} =0.5\,\text{A} \] \[ \boxed{0.5\,\text{A}} \]
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