Question:
The critical angle for glass-water interface (if \( \mu_g = \frac{3}{2}, \mu_w = \frac{4}{3} \)) is:
The critical angle for glass-water interface (if \( \mu_g = \frac{3}{2}, \mu_w = \frac{4}{3} \)) is:
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Critical angle uses \(\frac{\text{rarer}}{\text{denser}}\) and must always be \(< 1\).
Updated On: Jun 16, 2026
- \( \sin^{-1}\left(\frac{8}{9}\right) \)
- \( \sin^{-1}\left(\frac{9}{8}\right) \)
- \( \sin^{-1}\left(\frac{3}{2}\right) \)
- None of these
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Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Concept: \[ \sin C = \frac{\mu_{\text{rarer}}}{\mu_{\text{denser}}} \]
Step 1:
Glass is optically denser than water. \[ \sin C = \frac{\mu_w}{\mu_g} = \frac{4/3}{3/2} \]
Step 2: \[ \sin C = \frac{4}{3} \times \frac{2}{3} = \frac{8}{9} \] \[ C = \sin^{-1}\!\left(\frac{8}{9}\right) \]
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