




To determine the correct structure of compound C, we need to understand the reaction steps involved in the given chemical transformation. Here's the breakdown:
First, we have an organic molecule with a cyanide group: \(CH_3CH_2CN\).
The first reaction involves the addition of Grignard reagent \(CH_3MgBr\) in ether to form compound A. Grignard reagents add to nitriles to form ketones after hydrolysis. Specifically, the reaction can be explained as:
\(CH_3CH_2CN + CH_3MgBr \rightarrow CH_3CH_2C(=NMgBr)CH_3 \xrightarrow[\text{}]{H_3O^+} CH_3CH_2COCH_3\)
Next, compound A is hydrolyzed with \(H_3O^+\) to form compound B, which is a ketone: \(CH_3CH_2COCH_3\).
Compound B then undergoes Clemmensen reduction, which involves treatment with Zn-Hg and HCl to reduce the carbonyl group to a methylene group. The transformation can be summarized as:
\(CH_3CH_2COCH_3 \xrightarrow[\text{Zn-Hg}]{HCl} CH_3CH_2CH_2CH_3\)
Thus, the correct structure of C is butane (\(CH_3CH_2CH_2CH_3\)).
The given image of option A correctly represents this structure:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
Alcohols, phenols, and ethers are organic compounds that can be prepared by various methods.
Preparation of Alcohols:
Preparation of Phenols:
Preparation of Ethers:
In summary, alcohols, phenols, and ethers can be prepared by a variety of methods, including hydration, reduction, Grignard reaction, hydroboration-oxidation, hydrolysis, oxidation, Williamson synthesis, and dehydration. The choice of the method depends on the availability of starting materials, the desired product, and the conditions of the reaction.