Given below are two statements:
Statement (I): p-nitrophenol is more acidic than m-nitrophenol and o-nitrophenol.
Statement (II): Ethanol will give immediate turbidity with Lucas reagent.
In the light of the above statements, choose the correct answer from the options given below:
Statement (I): p-nitrophenol is more acidic than m-nitrophenol and o-nitrophenol.
Statement (II): Ethanol will give immediate turbidity with Lucas reagent.
In the light of the above statements, choose the correct answer from the options given below:
Both Statement I and Statement II are false
Both Statement I and Statement II are true
Statement I is true but Statement II is false
Statement I is false but Statement II is true
The Correct Option is C
Approach Solution - 1
To determine the correct answer, let's examine both statements separately:
- Statement I: p-nitrophenol is more acidic than m-nitrophenol and o-nitrophenol.
- P-nitrophenol (para-nitrophenol) is more acidic due to the electron-withdrawing nature of the nitro group that enhances acidity by stabilizing the phenoxide ion. In para position, the nitro group provides maximum resonance and inductive effects.
- In comparison, o-nitrophenol (ortho-nitrophenol) has steric hindrance and hydrogen bonding, which decreases its acidity compared to para. While m-nitrophenol (meta-nitrophenol) does not benefit from as much resonance or inductive effect.
- Therefore, p-nitrophenol is indeed more acidic than both m-nitrophenol and o-nitrophenol.
- Statement II: Ethanol will give immediate turbidity with Lucas reagent.
- Lucas reagent (a mixture of hydrochloric acid and zinc chloride) is used to distinguish between primary, secondary, and tertiary alcohols based on their reactivity, developing turbidity as an indicator.
- Tertiary alcohols react immediately with Lucas reagent to give turbidity, secondary alcohols require a few minutes, and primary alcohols usually do not react at room temperature.
- Ethanol is a primary alcohol, hence it will not give immediate turbidity with Lucas reagent.
- Thus, Statement II is false.
Based on the analysis above, Statement I is true as p-nitrophenol's greater acidity is correctly described, while Statement II is false as ethanol does not produce immediate turbidity with Lucas reagent.
Therefore, the correct answer is: Statement I is true but Statement II is false.
Approach Solution -2
Statement I: p-Nitrophenol is more acidic than m- and o-nitrophenol due to resonance stabilization and inductive effects.
Statement II: Ethanol reacts slowly with Lucas reagent, not giving immediate turbidity (which is typical of tertiary alcohols).
Thus, Statement I is correct, and Statement II is incorrect.
Top Questions on Alcohols, Phenols and Ethers
From the following, how many compounds contain at least one secondary alcohol?
- JEE Main - 2026
- Chemistry
- Alcohols, Phenols and Ethers
- How methanol is prepared industrially? Write the chemical equation.
- KBPE - 2026
- Chemistry
- Alcohols, Phenols and Ethers
Name the products formed when phenol is treated with the following reagents:
(i) Bromine water
(ii) Zinc dust
(iii) Conc. HNO_3- KBPE - 2026
- Chemistry
- Alcohols, Phenols and Ethers
(i) Predict the products A and B in the hydroboration-oxidation reaction.
(ii) Explain the preparation of phenol from cumene.- KBPE - 2026
- Chemistry
- Alcohols, Phenols and Ethers
- Why is Phenol more acidic than alcohols?
- NBSE Class XII - 2026
- Chemistry
- Alcohols, Phenols and Ethers
Questions Asked in JEE Main exam
- Let $\vec{a}=2\hat{i}-\hat{j}-\hat{k}$, $\vec{b}=\hat{i}+3\hat{j}-\hat{k}$ and $\vec{c}=2\hat{i}+\hat{j}+3\hat{k}$. Let $\vec{v}$ be the vector in the plane of $\vec{a}$ and $\vec{b}$, such that the length of its projection on the vector $\vec{c}$ is $\dfrac{1}{\sqrt{14}}$. Then $|\vec{v}|$ is equal to
- JEE Main - 2026
- Vector Algebra
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.- JEE Main - 2026
- Solutions
- The wavelength of photon 'A' is 400 nm. The frequency of photon 'B' is \(10^{16}\,\text{s}^{-1}\). The wave number of photon 'C' is \(10^{5}\,\text{cm}^{-1}\). The correct order of energy of these photons is:
- JEE Main - 2026
- General Chemistry
- Given below are two statements: Statement I: The increasing order of boiling point of hydrogen halides is HCl<HBr<HI<HF. Statement II: The increasing order of melting point of hydrogen halides is HCl<HBr<HF<HI. In the light of the above statements, choose the correct answer from the options given below:
- JEE Main - 2026
- General Chemistry
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]- JEE Main - 2026
- Ray optics and optical instruments
Concepts Used:
Alcohols, Phenols, and Ethers - Chemical Reactions
The reaction of alcohols:
- Reaction with Metal
- Reaction with Halides
- Reaction with HNO3
- Reaction with Carboxylic Acid (Esterification)
- Dehydration of Alcohol
- Haloform Reaction
The reaction of phenols:
- Formation of Ester
- Hydrogenation
- Oxidation of Quinones
- Electrophilic Substitution
- Halogenation
The reaction of ethers:
- Contact with Air
- Halogenation of Ether
- Electrophilic Substitution Reaction
Read More: Alcohols, Phenols, and Ethers