Question

The correct statement(s) about NO$_2$, NO$_2^+$ and CO$_2$ is/are

• A. Both NO$_2$ and CO$_2$ are paramagnetic.
• B. NO$_2$ is paramagnetic and NO$_2^+$ is diamagnetic.
• C. Both CO$_2$ and NO$_2^+$ have linear geometry.
• D. CO$_2$ and NO$_2^+$ are isoelectronic.

Hint:

To determine if a molecule is paramagnetic or diamagnetic, check for the presence of unpaired electrons in the molecular orbitals.

Answer 1

The Correct Option is B, C, D

Step 1: Analyze the properties of NO$_2$ and NO$_2^+$.
- NO$_2$ is a free radical with an odd number of electrons, which makes it paramagnetic.
- NO$_2^+$ has an even number of electrons, making it diamagnetic.
Step 2: Analyze CO$_2$.
CO$_2$ is a linear molecule with no unpaired electrons, and it is diamagnetic.
Step 3: Conclusion.
The correct statement is (B) NO$_2$ is paramagnetic and NO$_2^+$ is diamagnetic.